# Line slope calculator 2x+y=10

**Straight line given by points A[0; 10] and B[1; 8]**

## Calculation:

**Slope-intercept form of line:**y = -2x+10

**Canonical form of the line equation:**2x+y-10 = 0

**Parametric form of the line equation:**

x = t

y = -2t+10 ; t ∈ R

**Slope:**m = -2

**Slope angle of line: φ =**-63°26'6″ = -1.1071 rad

**X intercept:**x

_{0}= 5

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 4.4721

**The length of the segment AB: |AB| =**2.2361

**Vector: AB =**(1; -2)

**Normal vector: n =**(2; 1)

**Midpoint of the segment AB: M =**[0.5; 9]

**Perpendicular Bisector equation:**x-2y+17.5 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (1; 8) ; |OB| = 8.0623**

**Scalar product OA .OB = 80**

**Angle ∠ AOB = 7°7'30″ = 0.1244 rad**